To all my 5A, 5B and 5C students,
Wishing you all the best in your SPM 2012.
About Me
- cikgubio
- My name is Poon Cheng Moh. I have been teaching biology in SMK(P) Raja Zarina, Port Klang for 26 years. I sincerely hope that this blog on SPM Biology will be useful to both teachers and students.
Monday, November 5, 2012
Sunday, September 9, 2012
Answer to Hands on Pg 77-81
Objective Questions
1
|
A
|
9
|
D
|
2
|
C
|
10
|
D
|
3
|
D
|
11
|
C
|
4
|
B
|
12
|
C
|
5
|
A
|
13
|
D
|
6
|
A
|
14
|
A
|
7
|
C
|
15
|
B
|
8
|
D
|
|
|
Section A / Bahagian A
1. (a) (i) Genetic factor
(ii) Various alignments of
homologous chromosomes during metaphase together
with crossing over during prophase I
produce different combinations of alleles in gametes.
(b)(i) Draw a bar chart
(ii) Discontinuous variation
(iii) No intermediate values among
individuals, discrete distribution
(c) Thumbprints, blood groups
(d) The graph of the heights of
students shows normal distribution whereas the graph of the presence of dimples
shows discrete distribution. There are no intermediate values in the graph of
the characteristic of dimples whereas there are no clear cut values for the
range of values of students’ heights.
2. a (i)
Lengths (mm)
|
Number of earthworms
|
50-53
|
2
|
54-57
|
5
|
58-61
|
8
|
62-65
|
10
|
66-69
|
9
|
70-73
|
7
|
74-77
|
4
|
78-81
|
1
|
(ii) Draw a histogram
(b) (i) Continuous variation
(ii) There are intermediate values
(iii) Mass of earthworms, size of
earthworm
(c) (i) Earthworm in container P has the fastest growth rate.
(ii) Environmental factors such as
types of soil and the presence of light affect the growth of earthworms.
Wednesday, August 22, 2012
Sample answer to Question 1 Paper 3 (Pg 196 Bioscore)
a)
Pattern of thumbprints
|
No of students with the same pattern of thumbprint
|
Whorl
|
12
|
Loop
|
10
|
Composite
|
22
|
Arch
|
6
|
b) i)
1. The number of students
with the pattern of thumbprint composite is 22.
2. The number of students
with the pattern of thumbprint arch is 6.
(ii)
1. The number students with the
pattern of thumbprint composite is high because
it
is a dominant trait.
2. The number of students with the pattern of
thumbprint arch is low because it
is a recessive trait.
Variable
|
Method to handle the
variable
|
Manipulated variable
Pattern of thumbprints
|
Use different types
of thumbprints which are composite, loop, whorl and arch
|
Responding variable
Number of students with
the same pattern of thumbprints
|
Count and record the number of student with each pattern of thumbprint
by using thumbprint set.
|
Controlled variable
Type of fingers
|
Fix the type of finger
to be same
|
(d) When the pattern of
thumbprint is composite, the number of students is the highest.
(e)i)
Pattern of thumbprints
|
No of students with the same pattern of thumbprint
|
Whorl
|
12
|
Loop
|
10
|
Composite
|
22
|
Arch
|
6
|
(ii) Draw a bar chart
(f) The type of variation
found in thumbprint is discontinuous variation because the is no range/intermediate
values between the different thumbprint pattern and falls in a
distinct/discrete category.
(g) Bell shape/normal
distribution.
Height is a continuous
variation and it has intermediate values and is influenced by genetic and
environment factors.
Saturday, August 11, 2012
Answers to Hands-on Pg 65-69
Objective Questions
1
|
A
|
9
|
D
|
2
|
B
|
10
|
D
|
3
|
B
|
11
|
A
|
4
|
A
|
12
|
D
|
5
|
D
|
13
|
C
|
6
|
B
|
14
|
B
|
7
|
B
|
15
|
C
|
8
|
A
|
16
|
C
|
Structured Questions
Section A
1. (a) (ii) Tall plants with
coloured flowers
(b) (i) Dihybrid cross
(ii) TtCc
(d)(i)
Gametes
|
TC
|
Tc
|
tC
|
tc
|
tc
|
TtCc
|
Ttcc
|
ttCc
|
ttcc
|
(ii) A plant which is heterozygous
for tallness and coloured flowers has the genotype TtCc. The plant produces
four types of gametes, TC, Tc, tC and tc. When the plant is crossed with another
plant which is homozygous recessive, the gametes combine at random to produce plants
with TtCc, Ttcc, ttCc and ttcc as their genotypes.
(e) To obtain consistent results as
pure-breeding plants are able to produce offspring which have received
identical genes from the parents. When self-fertilised, they are able to
produce offspring having exactly the genes they have inherited.
2. (a) (i) Genes are carried on the sex
chromosomes and passed down to the next generation.
(ii) Usually are carried on the X
chromosome and it mostly affects the males
(b) Bakri’s mother must be a carrier
with the genotype XHXh in which ‘h’ is the recessive gene
for haemophilia. Bakri inherits Xh from his mother and the Y
chromosome from his father.
(c) One of them inherits XH
from her father and XH from her mother. The other one inherits XH
from her father and Xh from her mother. Both are normal but
genotypically, one of them is a carrier.
(d) Males are determined by the
presence of the X and Y chromosomes. Sex-linked genes are absent in the Y
chromosomes. Therefore, the presence of one sex-linked gene in the X chromosome
will affect the male as compared to the female who
needs genes to be present in both X
chromosomes for her to be affected.
(e)
Gametes
|
Xh
|
Y
|
XH
|
XHXh
|
XHY
|
Xh
|
Xh
Xh
|
XhY
|
(f) 100%
Answers to Hands-on Pg 63-64
Aim : To
illustrate Mendel’s first law using coloured buttons
Colours of buttons
|
Number of pairs
|
Trait represented by buttons
|
Red and red
|
24
|
Tall
|
Red and white
|
53
|
Tall
|
White and white
|
23
|
Dwarf
|
Discussions:
- Red
- Gamete
- Tall plant. Red button represent the gene for tallness which is dominant. Therefore when it is paired with a white button which is recessive, then a tall plant is produced. A dominant gene expresses itself even when it is in the heterozygous condition.
- The ratio of tall : dwarf is 3:1. This is because an organism’s characteristic is determined by a pair of genes which will separate and be carried in a gamete and the dominant gene will express itself.
Conclusion
:
Mendel’s
first law is illustrated by separating the buttons before pairing them again
which shows that a characteristic in an organism is represented by a pair of
genes. The genes will separate and each gene is carried by a gamete.
Answer to Hands - on Pg 54-56
Objective Questions
1
|
B
|
11
|
D
|
2
|
D
|
12
|
C
|
3
|
B
|
13
|
D
|
4
|
B
|
14
|
D
|
5
|
C
|
15
|
A
|
6
|
D
|
16
|
B
|
7
|
B
|
17
|
C
|
8
|
B
|
18
|
B
|
9
|
C
|
19
|
A
|
10
|
B
|
|
|
1. (a) P : 2n Q : n R : n
(b) W : Mitosis
X : Meiosis I
Y : Meiosis II
(c)
Spermatogonium →Primary
spermatocyte→Secondary
spermatocyte →Spermatid
→
Spermatozoa
(d) (i) Mitochondrion
(ii) To produce energy through
cellular respiration for the sperms to swim to the ovum
(iii) To propel the sperm forward
when swimming towards the ovum
(e) Artificial insemination in which
sperms from a donor can be obtained from a sperm bank and injected into the
uterus of a woman during ovulation.
2. (a) (i) Root cap
(ii) Protects the root tip
(b) (i) Zone of cell division
(ii) Draw on your own
(c)(i) Draw on your own
(ii) Cell in zone Q absorbs water through osmosis. The
vacuole expands and pushes
the cytoplasm against the cell wall.
The cell elongates.
(d) Xylem and phloem
(e) Draw on your own
3. (a)
Growth curve of a rat: Sigmoid curve
Growth curve of a cockroach: Series
of steps
(b) (i) Early phase
(ii) Mainly cell division through
mitosis where growth rate is slow
(c)(ii) In the exponential phase,
growth speeds up exponentially. The number of cells increases and cells
increase in size quickly. In the maturity phase, growth slows down as it reaches
maturity.
(d) (i) X is a stage of ecdysis.
(ii) The cockroach takes in air to
expand its body. The old exoskeleton is shed to expose the new and soft
exoskeleton beneath it. Growth of organs and tissues takes place quickly before
the new exoskeleton hardens.
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